x^2+22x=455

Solution for x^2+22x=455 equation:

x^2+22x=455

We move all terms to the left:

x^2+22x-(455)=0

a = 1; b = 22; c = -455;
Δ = b2-4ac
Δ = 222-4·1·(-455)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-48}{2*1}=\frac{-70}{2}
=-35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+48}{2*1}=\frac{26}{2}
=13
$